3n+1 Run TIme Error

[anjaneyanjan7]

Code: Select all

#include <iostream>


using namespace std;

int main()
{
   long long a,c,b,*arr,i,max=0,n,num;
   
   while(cin >> a >> b){
      arr = new long long[b-a];
      
   
      if(a>b){
        c = a;
        a = b;
        b = c;
      }
      
      max = 0;
      for(i=0;i<b-a+1;i++){
         arr[i] = a+i;
      }

      for(i=0;i<b-a+1;i++){
         n = arr[i];
         num=1;
      
         while(n!=1){
            num++;
            if(n<=b && n>=a)
                   arr[n-a] = 1;   
            if(n%2 == 0){
               n = n/2;
            }
               
            else
               n = 3*n + 1;
         }
         if(max < num)
            max=num;
      }
      
      cout << a << " " << b << " " << max<<endl;      

   }
      return 0;
}


kindly let me knw why I am getting runtime error message

Hi,

This is an automated response from UVa Online Judge.

Your submission with number 8368446 for the problem 100 - The 3n + 1 problem has failed with verdict Runtime error.

This means that the execution of your program didn't finish properly. Remember to always terminate your code with the exit code 0.

Best regards,

The UVa Online Judge team

[niemic]

The max number of elements is greater than your array.

Example:

input value of 3 -> 3 10 5 16 8 4 2 1 , so there will be 8 elements