by Md. Aftabuddin » Sat Jul 30, 2005 3:41 pm
[quote="little joey"]Their area, but that's completely irrelevant for the problem.
Two triangles (a,b,c): a>=b, b>=c and (a',b',c'): a'>=b', b'>=c' are "similar" (i.e. have the same "style") iff a/a' == b/b' == c/c'.
If you split the two triangles (4,5/2,5/2) and (3,5/2,5/2) again, you get four equal triangles (5/2,2,3/2) (truely equal (congruent) this time), which are similar to the original triangle.[/quote]
The area is equal in the case of isoceles,equilateral and right tringle but not for general tringle