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mohiul alam prince wrote:Hi
I have solve this problem by this way
- First i have stored some prime number
- Then i have stored number of factor's in a single number by using DP.
- Then binary search
MAP
0
1
10000001
-200
Case 1: 0!
Case 2: 2!
Case 3: 2703663!

mohiul alam prince wrote:Hi
I have solve this problem by this way
- First i have stored some prime number
- Then i have stored number of factor's in a single number by using DP.
- Then binary search
Thanks![]()
MAP


Table[i] = Table[i / prime[j]] + Table[prime[j]];
Table[0]=0
Table[1]=0
Table[2]=1
Table[3]=1
Table[4]=2
Table[5]=1
Table[6]=2
Table[7]=1
Table[8]=3
...Table[4]+Table[3]+Table[6]+Table[2]Table [ 4 * 3 * 6 * 2 ] = Table[144]Users browsing this forum: No registered users and 1 guest