362 - IO tricky samples

[CDiMa]

Sorry, what i mean is "ceil"
i made the mistake when i posted the topic

Are you sure that it was your mistake and not that your source uses ceill?
ceill is a valid C99 function and handles long double...

Ciao!!!

Claudio

[Rajib]

I can't believe myself . . .

I get WA with;

remaintime=ceil(remainbyte/(transferbyte/5.0));
printf(" Time remaining: %ld seconds\n",long(remaintime));

I get AC with;

remaintime=remainbyte/(transferbyte/5.0);
printf(" Time remaining: %ld seconds\n",long(ceil(remaintime)));

only chainge is ceil in printf function...

[CDiMa]

I can't believe myself . . .

I get WA with;

remaintime=ceil(remainbyte/(transferbyte/5.0));
printf(" Time remaining: %ld seconds\n",long(remaintime));

I get AC with;

remaintime=remainbyte/(transferbyte/5.0);
printf(" Time remaining: %ld seconds\n",long(ceil(remaintime)));

only chainge is ceil in printf function...

What is the type of the remaintime variable?

Ciao!!!

Claudio

[CodeMaker]

Hi, I got Acc after 7 WA and all credit goes towards u sjn. This problem made me sick....

[dootzky]

seriously, this is one of the problems that make you hate problem solving...

it's fairly simple, but it has a catch. like SJN said, you must do EXACTLY the following, or you won't get ACC.

remainSecond = remainBytes / (transferedBytes/5.0);
printf("%d seconds\n", ceil(remainSecond));

thx SJN for your insight.
but i still don't get it.

[stcheung]

Yeah I also got AC after doing the following:
float remainSecond = remainBytes / (transferedBytes/5.0);

instead of something like:
float transferrate = (transferedBytes/5.0)
float remainSecond = remainBytes / transferrate;

Other than that, you can just use int and float for all your variables. No tricky input, though I wonder what it uses so much memory for. One additional security measure I took is (int)(ceil(remaining)+0.2) which I don't believe is really needed though based on the thread.

[johnplayers]

I also got AC after what sjn told us to do. I was frustrated at not having been able to submit it for 3 days.

[gvs]

Man....
such problems are crap....
though I didn't divide by 5.0....
instead i used rate=0.2*transferredbytes;
and then remaintime=ceil(remainbytes/rate);
then used %.0lf to printf the answer....

but if i used rate=transferredbytes/5.0;
then that ceil problem cropped up.... giving me WA.

another thing is that using '\t' for the 'Time remaining' message, gave me PE, whereas, using 'bbbTime remaining:'' (b=blank) gave me AC....
strange.....
does \t signify different lengths in different platforms ???

[alamgir kabir]

I have got it accepted but very much surprised!!!!!!!!!
Ii's a very much technical and fraction error.
so everyone be careful to handle fraction errors.
I type cast the double into long
Thanks all

[ligregni]

Hi, I'm desesperate, I need help!,

I have revewed all the output sentences, I tried all the cases I've found and they are OK!,

I also tried printing after each case (including last one) "\n\n", or printing after each case (including last) "\n", but printing after each case (except the last) "\n" (all of this is printing two \n after all cases exept the last, where I only print one) or printing "\n\n" after all cases except last one (who is "empty" after him),

I tried printing all of this combinations after scanning the # of bytes or before that (I need your help giving me the answer of the \n issue, it will help a lot),

I am almost sure the Math issue is correct (for avoid ceil(), I made the same calculus whith a double and an integer, if they are not the same, I print the integer (long actually) plus 1),

I remember you I've tried with all cases I've found and some extrem I thinked (for example, 10000 bytes, and in the first 5 seconds just one byte has been transferred, and after that one stalled, and then all the bytes less one tranfers, and calculus the time remaining),

I also checked all the ':' and that stuff,

I'm getting crazy with this problem,

I know it's OK, but UVa doesn't think the same, and I'm pretty sure it is by any little thing, but I don't know, what, so, here is my code:

Code: Select all

/* 18,000 Seconds Remaining */

#include <stdio.h>

int main ()
{
/* FILE *in = freopen ("c.in", "r", stdin); /**/

   long b=0, B=0, c=0;

   scanf("%i", &b);

   while (b!=0)
   {
      c++;

/*      if (c!=1)
         printf("\n");

*/
      long sec=0, time[5];

      printf("Output for data set %d, %d bytes:\n", c, b);

      B=0;

      while (B<b)
      {
         scanf("%i", &time[sec%5]);

         B += time[sec%5];

         sec++;

         if (sec%5==0)
         {
            long suma=0, x=0;

            double t=0.0;

            while(x++<5)
               suma += time[x-1];

            t = suma/5.0;



            double d=0;

            if (t!=0)
            {
               x = (b-B)/t;

               d = (b-B)/t;

               if (x!=d)
                  x++;
            }

            printf("   Time remaining: ");

            if (t==0)
               printf("stalled\n");
            else
               printf("%i seconds\n", x);
         }
      }

      printf("Total time: %i seconds\n", sec);

      scanf("%i", &b);

      if (b!=0)
         printf("\n");



   }

   return 0;
}



This version of my code is the one who prints \n after all cases and another \n after all cases except last one.

I get WA at 0.190 secs aprox, so I know it could be almost at the end.

aprox 5 of my WA was because I forgot to comment the FILE *in line, but I have trained myself to avoid that.

THANKS

Sergio Ligregni

[kbr_iut]

AC,,,code deleted..
Its too pathetic that,,,when I used ceil(double vale) i got WA
when i used ceil(double value+1e-7)i got WA
when I used (int)(double value+.9999999)i got AC....but why?
so think everyone how much one should b careful calculating floating point numbers!

[fR0D]

can somebody please point out why am i getting WA?

Code: Select all

Got AC.
Changed the line
printf("   Time remaining: %.0f seconds\n",ceil(remainingBytes/((float)transferedBytes/5.0)));
to
printf("   Time remaining: %.0f seconds\n",ceil(remainingBytes/((double)transferedBytes*0.2)));
and GOT AC.


i tried all test cases on forum and got expected answer still WA.

[kbr_iut]

u can use that technic posted immediate before u.
suppose
double d contains ur result. u need to round (to ceil)
just use this
long=tem=(int)(d+.9999999);
print tem;

hope it will help.

[abid_iut]

why WA it is giving every output right
here is the code:

Code: Select all

#include<stdio.h>
#include<math.h>

int main()
{
   long size,time,count,sum,n=1,byte,line=0;
   double aver,remainsecond;
   while(scanf("%ld",&size)==1&& size){
         if(line)printf("\n");
         line=1;
   printf("Output for data set %ld, %ld bytes:\n",n++,size);
   sum=0;time=0;count=0;aver=0;
   while(sum!=size){
      scanf("%ld",&byte);
      sum+=byte;
      aver+=byte;
      count++;
      time++;
      if(count==5){
         count=0;
         if(aver==0)printf("   Time remaining: stalled\n");
         else {
            remainsecond=(size-sum)/(aver/5.0);
            printf("   Time remaining: %.0lf seconds\n",ceil(remainsecond));
         }
         aver=0;
      }
   }
   printf("Total time: %ld seconds\n",time);
   }
   return 0;
}



[kbr_iut]

abid_iut.
check ur pm inbox.