11715 - Car

[sms.islam]

I have got WA for this problem.Is there any trick with that problem?

can anyone please send some spical input for this problem?

my algorithom()
{
while(scanf("%ld",&n)!=EOF)
{
if(n==1)
{
print desired result;
}

else if(n==1)
{
print desired result;
}

else if(n==1)
{
print desired result;
}
.................................................
}
}

whats wrong with that?

[r2ro]

Well, why are your conditional statements only if n == 1?

[naseefcuet]

@sms.islam
post your code.....This is a simple problem....there should be some sill ymistakes in your code....

[sms.islam]

// Code removed cause Accepted

thanx naseefcuet i got it.

[naseef_07cuet]

@s.islam
check this code...and make the correction from your code:-:
read (c);
if(c==0)
break;
if(c==1)
read (u,v,t);
a=(v-u)/t;
s=(v*v-u*u)/(2*a);
if(c==2)
read(u,v,a);
t=(v-u)/a;
s=(v*v-u*u)/(2*a);
if(c==3)
read(u,a,s);
v=sqrt((u*u+2*a*s));
t=(v-u)/a;
else if(c==4)
read(v,a,s);
u=sqrt((v*v-2*a*s));
t=(v-u)/a;
Hope you will get it........

[Eather]

why WA?? i got AC with the same code once i submitted 1st time.

Code: Select all

#include<stdio.h>
#include<math.h>
#include<iostream>
using namespace std;

int main()
{
    int n;
    long double a, b, c;
    int i = 1;
    while ((scanf("%d %lf %lf %lf",&n,&a,&b,&c))==4)
   {
       if (n == 1)
      {
          long double res2 = (b-a)/c;
          long double res1 = (a*c) + (0.5*res2*c*c);
          printf("Case %d: %0.3lf %0.3lf\n", i, res1, res2);
       }
       if (n == 2)
      {
          long double res2 = (b-a)/c;
          long double res1 = (a*res2) + (0.5*c*res2*res2);
          printf("Case %d: %0.3lf %0.3lf\n", i, res1, res2);
       }
       if (n == 3)
      {
          long double res1 = sqrt(a*a + 2*b*c);
          long double res2 = (res1-a)/b;
          printf("Case %d: %0.3lf %0.3lf\n", i, res1, res2);
       }
       if (n == 4)
      {
          long double res1 = sqrt(a*a - 2*b*c);
          long double res2 = (a-res1)/b;
          printf("Case %d: %0.3lf %0.3lf\n", i, res1, res2);
       }
       i++;
    }
 
 }


help me please

[vkshibbir]

Why WA?

Code: Select all

#include<stdio.h>
#include<math.h>

int main()
{
    int i;
    int a;
    double  b,c,d;
    double  u,v,ac,s,t;
    for(i=1;; i++)
    {
        scanf("%d",&a);
        if(a==0)break;
        scanf("%lf %lf %lf",&b,&c,&d);

        printf("Case %d: ",i);

        if(a==1)
        {
            u=b;
            v=c;
            t=d;
            ac=(v-u)/t;
            s=u*t+.5*ac*t*t;
            printf("%.3lf %.3lf\n",s,ac);
        }
        if(a==2)
        {
            u=b;
            v=c;
            ac=d;
            s=(v*v-u*u)/(2*ac);
            t=(v-u)/a;
            printf("%.3lf %.3lf\n",s,t);
        }
        if(a==3)
        {
            u=b;
            ac=c;
            s=d;
            v=sqrt((u*u+2*ac*s));
            t=(v-u)/ac;
            printf("%.3lf %.3lf\n",v,t);
        }
        if(a==4)
        {
            v=b;
            ac=c;
            s=d;
            u=sqrt(v*v-2*ac*s);
            t=(v-u)/ac;
            printf("%.3lf %.3lf\n",u,t);
        }
    }
    return 0;
}

help me please

[reza_uranium]

Why WA...plz help me

#include <stdio.h>
#include <math.h>

int main()
{
int i,n;
double s,a,u,v,t;

for(i=1;;i++){
scanf("%d",&n);

if(n==0){
break;
}

if(n==1){
scanf("%lf %lf %lf",&u,&v,&t);

s=((u+v)/2.0)*t;
a=(v-u)/t;

printf("Case %d: %.3lf %.3lf\n",i,s,a);
}
if(n==2){
scanf("%lf %lf %lf",&u,&v,&a);

t=(v-u)/a;
s=u*t+.5*a*t*t;

printf("Case %d: %.3lf %.3lf\n",i,s,t);
}
if(n==3){
scanf("%lf %lf %lf",&u,&a,&s);

v=sqrt(2*a*s+u*u);
t=(v-u)/a;

printf("Case %d: %.3lf %.3lf\n",i,v,t);
}
if(n==4){
scanf("%lf %lf %lf",&v,&a,&s);

u=sqrt(u*u-2*a*s);
t=(v-u)/a;

printf("Case %d: %.3lf %.3lf\n",i,u,t);
}
}

return 0;
}

[brianfry713]

Input:

Code: Select all

3 6 1 6
4 5.0 -1 6
0

AC output:

Code: Select all

Case 1: 6.928 0.928
Case 2: 6.083 1.083


[raj]

Deleted

[brianfry713]

See what happens with 10 or more input cases.

[raj]

thanks sir Now its accepted