587

[sushil2006090]

#include<iostream>
#include<fstream>
#include<cmath>
#include<algorithm>
#include<iterator>
#include<stack>
#include<list>
#include<queue>
#include<set>
#include<string>
#include<map>
#include<functional>
#include<utility>
#include<vector>
#include<deque>
#include<iomanip>
typedef long long LL;
typedef unsigned long UL;
using namespace std;
int main()
{
string str;
int map=1;
while(true)
{
cin>>str;
if(str=="END")
break;
float x=10e-6,y=10e-6;
int len=str.length();
for(int i=0;i<len-1;)
{
string s,st;
while(isdigit(str[i]))
{
s+=str[i];
i++;
}
st+=str[i];
i++;
if(str[i]!=','&& str[i]!='.')
st+=str[i];
i++;
// cout<<s<<" "<<st<<endl;
int l=s.length();
double temp=0;
int mult=1;
for(int i=l-1;i>=0;i--)
{temp+=(s[i]-'0')*mult;mult*=10;}
//cout<<temp<<endl;
if(st=="N")
{ y+=temp;}
else if(st=="S")
y-=temp;
else if(st=="E")
x+=temp;
else if(st=="W")
x-=temp;
else if(st=="SW")
{
x-=temp*sin(2*acos(0)/4);y-=temp*sin(2*acos(0)/4);
}
else if(st=="NW")
{x-=temp*sin(2*acos(0)/4);y+=temp*sin(2*acos(0)/4);}
else if(st=="NE")
{x+=temp*sin(2*acos(0)/4);y+=temp*sin(2*acos(0)/4);}
else if(st=="SE")
{x+=temp*sin(2*acos(0)/4);y-=temp*sin(2*acos(0)/4);}
//cout<<x<<" "<<y<<endl;
//cout<<x<<" "<<y<<endl;

}
cout<<"Map #"<<map<<"\n";
map++;
printf("The treasure is located at (%.3f,%.3f).\n",x,y);
printf("The distance to the treasure is %.3lf.\n\n", sqrt(x*x+y*y));

}
// system("pause");
}

[Shafaet_du]

1.no need to use long double.
2. you DON'T need any eps anywhere in this problem,i got accepted without using any.
3. don't forget to TYPECAST if you divide an integer by an integer and store the result in a double.
4. print blank line after EACH output. also check your spelling,don't miss the fullstops.
4. try this inputs:

Code: Select all

3E,4N,10W,5NE.
10NE,10SE,10NW,10NE
19SW,19S,19W,19SW,28NE
27S,18N,10S,10N,3W,13NW,14SW,14NW
10S,10N,10N,10S
END

output:

Code: Select all

Map #1
The treasure is located at (-3.464,7.536).
The distance to the treasure is 8.294.

Map #2
The treasure is located at (14.142,14.142).
The distance to the treasure is 20.000.

Map #3
The treasure is located at (-26.071,-26.071).
The distance to the treasure is 36.870.

Map #4
The treasure is located at (-31.991,0.192).
The distance to the treasure is 31.992.

Map #5
The treasure is located at (0.000,0.000).
The distance to the treasure is 0.000.



Hope you'll get ac. happy programming

[shellexecutor]

I can't figure out why I am getting WA.
Can someone help?

Code: Select all

#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <cmath>
#include <cfloat>

int main() {
    for ( int i=1; ; i++ ) {
        char guide[50000];
        gets(guide);
        if ( strcmp(guide, "END") == 0 ) break;
       
        if ( i>1 ) printf("\n");
       
        char *command = strtok( guide, ",." );
        double x = DBL_EPSILON, y = DBL_EPSILON;
       
        while ( command != NULL ) {
            if ( strstr(command, "NE") != NULL ) {
                x += atoi(command) / sqrt(2);
                y += atoi(command) / sqrt(2);
            } else if ( strstr(command, "NW") != NULL ) {
                x -= atoi(command) / sqrt(2);
                y += atoi(command) / sqrt(2);
            } else if ( strstr(command, "SE") != NULL ) {
                x += atoi(command) / sqrt(2);
                y -= atoi(command) / sqrt(2);
            } else if ( strstr(command, "SW") != NULL ) {
                x -= atoi(command) / sqrt(2);
                y -= atoi(command) / sqrt(2);
            } else if ( strstr(command, "N") != NULL ) {
                y += atoi(command);
            } else if ( strstr(command, "E") != NULL ) {
                x += atoi(command);
            } else if ( strstr(command, "W") != NULL ) {
                x -= atoi(command);
            } else if ( strstr(command, "S") != NULL ) {
                y -= atoi(command);
            }
           
            command = strtok( NULL, ",." );
        }
       
        printf("Map #%d\n", i);
        printf("The treasure is located at (%.3lf,%.3lf).\n", x, y);
        printf("The distance to the treasure is %.3lf.\n", sqrt(x*x+y*y)+DBL_EPSILON);
    }
   
    return 0;
}


[brianfry713]

Print a blank line after each test case, including the last one.