11428 - Cubes

[Obaida]

I don't know what's going on with me. Some one please help me to get ACC.
I got so many WA.

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removed

[Jan]

Read the description please. 'If there is more than one solution then output the one with smallest value of y.'
I think you are maximizing y.

[Obaida]

Oh....
tomorrow i was kidding with my self.
Thank for fixing mistake.

[shafin.MIST]

What's the prb in this code!!!!!!!!!!! its freaking me off

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#include<stdio.h>
#include<string.h>
int main()
{
//   freopen("input.txt","r",stdin);
//   freopen("output.txt","w",stdout);
   long int i,j,y,N;
   int digits[10005][2];
   for(i=1;i<100;i++)
      {
         for(j=1;j<i;j++)
         {
            y=i*i*i-j*j*j;
            if(y<=10000 && digits[y][0]<0)
            {
               digits[y][0]=i;
               digits[y][1]=j;
            }
         }
      }
   while(scanf("%ld",&N))
   {
      
      if(N==0)break;
      if(digits[N][0]>0)
         printf("%d %d\n",digits[N][0],digits[N][1]);
      else
         printf("No solution\n");
   }
   return 0;
}

[santosh]

[code][/code]

#include<stdio.h>
#include<math.h>

int main()
{
int flag , j , k , k1 ;
int i , temp , temp1 ;
int a[50] , b[50] ;

for(j=0 ; j<50 ; j++)
a[j] = pow(j , 3) ;

while( scanf("%d" , &i ) == 1 )
{
if( i == 0 )
break ;

for(j=0 ; j<50 ; j++)
b[j] = 0 ;

k=0 ;
for(j=0 ; j<50 ; j++)
{
if( a[j] <= i )
b[k++] = a[j] + i ;
else if( i > a[j] )
break ;
}


flag=0 ;
k=0 ;
for(j=0 ; j<50 ; j++)
{
for(k1=0 ; k1<50 ; k1++)
{
if( b[k1] == a[j] )
{
temp = j ;
flag = 1 ;
break ;
}
}
}

temp1 = a[temp] - i ;

for(j=0 ; j<50 ; j++)
{
if( a[j] == temp1 )
{
temp1 = j ;
break ;
}
}

if( flag == 1 && temp > temp1 && temp1 >= 0 )
printf("%d %d\n" , temp , temp1 ) ;
else
printf("No solution\n") ;
}
return 0 ;
}
[quote][/quote] can anyone give me speial test case???find any bug???

[Gabrielwer]

Thanx for the codes!!cell phone tracking it's highly appreciated I’ve manipulated the code and I’m using it to help others. I hope that is fine ;D

[alimbubt]

I am getting continuously wrong answer..Please help me......
Here is my code...

#include<stdio.h>
int main()
{
int n,x,y,i,j,flag,m;
while(scanf("%d",&n)==1)
{
if(n==0) break;
x=0;
y=0;
flag=0;
for(j=0;j<=22;j++)
{
for(i=1;i<=28;i++)
{
if(i<j) continue;
m=(i*i*i)-(j*j*j);
if(m==n)
{
x=i;
y=j;
flag=1;
break;
}
}
if(flag==1) break;
}
if(x==0&&y==0)
printf("No solution\n");
else
printf("%d %d\n",x,y);
}
return 0;
}

[brianfry713]

40*40*40-39*39*39=4681

[alimbubt]

40*40*40-39*39*39=4681

Thanks

[mahbub2012]

why wrong ans

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#include<stdio.h>
#include<math.h>

int main()
{
    double f,t;
    int i,c,n;
    int flag=0;

    while(scanf("%d", &n)==1) {
        if(n==0)
        break;

    for(i=1; ; i++) {
zz:

if(flag == 1)
{i=i+1;
flag=0; }

    f = n + (i*i*i);
    t = cbrt(f);
    c = t;



    if(i>=t)
    break;

    if(c == t)
    {flag = 1;
    break;}  }

    if(n!=((c*c*c)-(i*i*i)) && flag == 1)
    goto zz;

    if(flag == 1)
    { printf("%d %d\n", c,i);
    flag = 0; }

    else
    printf("No solution\n");

}

return 0;
}






[brianfry713]

That doesn't match the sample I/O.

[shuvrothpol1]

i've got wa many times.but i check the sample test cases here .can anyone help?
#include <stdio.h>

int main ()
{
long long int n,i,x2,y2,x2y2,flag,alert,j;
scanf ("%lld",&n);
while (n!=0){
j=1;
flag=0;
alert=0;
while (1){
for (i=0;i<j;i++){
x2=j*j;
y2=i*i;
x2y2=x2+y2;
if (x2y2>n){
alert=1;
break;
}
x2y2+=(i*j);
x2y2*=(j-i);
if (x2y2==n){
printf ("%lld %lld\n",j,i);
flag=1;
}
}
if (alert==1)
break;
j++;
}
if (flag==0)
printf ("No solution\n");

scanf ("%lld",&n);
}
return 0;
}

[brianfry713]

Try input:

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721
0

AC output:

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9 2

[shuvrothpol1]

tnx acceptep..