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Try this case:
2345515 3444441325 3444441325

Krzysztof Duleba
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Posts: 584
Joined: Thu Jun 19, 2003 3:48 am
Location: Sanok, Poland

### o...

my program outputs 2345515!!!!
thanks u very much.
zzzzzddddd
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Posts: 6
Joined: Tue Sep 21, 2004 5:53 pm

hi !
I got WA, and i can't figure it out.

1. I translate N,L,U to binary bit.
2. I use a temp array to store the reslut.
3. First, I copy the data from U to temp, and from leading bit to decide following two case.
if(U[i]==0&&N[i]==0)

I check if I changed the value and it wouldn't exceed the limit(up).
else if(U[i]==1&&N[i]==1)

This part is a little bit complicated for I to explain.
I try to minus 1 for this case ,so I change the value to 0 , and set all rest bits to 1. And then I check it wouldn't exceed the limit(down).
If it's smaller than the lower bound I reset the data as original one.
It starts from the largest one toward smaller one, so I don't have to handle the case
Code: Select all
U[i]==1&&N[i]==0
U[i]==0&&N[i]==1

for it has been the maxium we wanted.

if my statement can't help you to help me, just give me some critical I/O.
As Krzysztof Duleba posted my output
Code: Select all
9
4
17
435
905
625
409
712
14721
23460
29462
19554
17216
382924
237589
257219
234343
499600
14223127
16692359
13133233
19429997
10902496
957429345
1305069817
1880088222
704659827
1542920241

I use unsigned int to store data input and use << to pick out every bit and store in a int array.
As the problem statement
Code: Select all
given a 32-bit unsigned integer

I don't think there is any input over 2147483648.

james299
New poster

Posts: 10
Joined: Tue Jul 26, 2005 8:58 am
Location: Taiwan

I find what's wrong in my code. And AC now .

My judger for upper and lower limits are both wrong when difference is one.

Input

Code: Select all
127 50 60

My output

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51

But should be

Code: Select all
50

Good luck!
james299
New poster

Posts: 10
Joined: Tue Jul 26, 2005 8:58 am
Location: Taiwan

### 10718 WA

hi i am getting WA in this problem. now i checked my code with the sample given in the other post .. they don't match but i dont know whats wrong with my code or algo. can anyone check it plz?

Code: Select all
unsigned int L,U,N;

unsigned int get_M();

int main()
{
while(1)
{
cin>>N>>L>>U;
if(cin.eof())   break;
cout<<get_M()<<endl;
}

return 0;
}

unsigned int get_M()
{
unsigned int M,t;
int i;

for(M=L,i=31;i>=0;i--)
{
if(!(N&(1<<i))) //if the ith bit is OFF
{
t=M|(1<<i);   //turn ON the ith bit of M

if(t<=U)
M=t;
}
}

return M;
}
predator
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Posts: 3
Joined: Sun Jun 25, 2006 6:33 pm

### Re: 10718 WA

predator wrote:hi i am getting WA in this problem. now i checked my code with the sample given in the other post .. they don't match but i dont know whats wrong with my code or algo. can anyone check it plz?

Consider using (1u<<31) instead of (1<<31).

Martin Macko
A great helper

Posts: 481
Joined: Sun Jun 19, 2005 1:18 am
Location: European Union (Slovak Republic)

### Re: 10718 - Bit Mask

Try these test cases

inputs
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2709727097 1717317173 3015630156
1142911429 2225322253 3015630156
3083430834 3060830608 3230932309
2832328323 1288712887 3230932309
1390913909 1367713677 3230932309
2150721507 53335333 3230932309
21072107 2429024290 3230932309
3274332743 2447124471 3230932309
2660126601 1153311533 3265532655

outputs
Code: Select all
2122111110
3013643834
3224802381
1462638972
2904053386
2144245788
3230930708
3168118200
1634840694
CSGrandeur
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Posts: 5
Joined: Tue Aug 16, 2011 11:15 am

### Re: 10718 - Bit Mask

I'm getting WA in this problem..What I did is setting ans initially to zero..then checking every bit starting from MSB,if its zero,then set that bit in "ans",and check whether the new ans is smaller than upper limit,if yes,then set that bit,otherwise didn't set.When 1 found in any bit,made that bit 0 in ans and every smaller bit 1,then check whether this new value is greater or equals to lower limit,if yes,then set that bit to zero,otherwise one.I think there might be problem in handling long or unsigned..my algo seems ok,don't know whats wrong..someone please help,what's wrong with my code?
Code: Select all
AC
Last edited by sadia_atique on Wed Jun 06, 2012 5:24 pm, edited 1 time in total.
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Posts: 25
Joined: Thu Nov 24, 2011 6:32 am

### Re: 10718 - Bit Mask

New poster

Posts: 25
Joined: Thu Nov 24, 2011 6:32 am

### Re: 10718 - Bit Mask

Try the I/O CSGrandeur posted.
brianfry713
Guru

Posts: 1742
Joined: Thu Sep 01, 2011 9:09 am
Location: San Jose, CA, USA

### Re: 10718 - Bit Mask

Thanks,Got AC..a stupid mistake in loop..
New poster

Posts: 25
Joined: Thu Nov 24, 2011 6:32 am

### Re: 10718 - Bit Mask

I used this algorithm for this question:
I start with a mask equal to 0. I find the MSB in U then try to set corresponding bit in the mask 1 in the condition that 1) the result is less than U
and 2) if this bit is 0 in N or it's 1 but if we don't set this bit, with the remaining bits we can't produce a number which is greater than or equal to L.
Can anyone tell me what's is wrong with this algorithm??? because I keep getting WA!:-(
Here is my code: (I know it produces wrong result for 2 cases in the sample input provided in this forum but I can't understand why!)
Thanks.

Code: Select all
Algorithm is correct it was because of a simple mistake in implementation that I'd got WA.
AKJ88
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Posts: 17
Joined: Wed Feb 13, 2013 10:48 am

### Re: 10718 - Bit Mask

I got AC with the following "greedy" method, but I dont know why it works : assigned M = U and M = L . For each value of M , I check every bit position from 32 down to 0 if I can turn it on or turn it off. I can turn it on if the current bit in N is off , and by turned on the value of M still smaller than U . I can turn it off if the current bit in N is on , and by turned off the value of M still bigger than L . Then I simply compare the value of N^M in each case and get the result.
tiendaotd
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Posts: 12
Joined: Mon Jan 14, 2013 12:21 pm

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