## 10719 - Quotient Polynomial

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### 10719 - Quotient Polynomial

I cant uderstand what is wrong.
Victor Barinov
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Hello Victor Barinov.
I think if your algo is right you won't get WA, because I think ther aren't spesial cases.Tell me your algorithm and may be I can help you.

Eduard.
someone who like to solve informatic problems.
http://acm.uva.es/cgi-bin/OnlineJudge?AuthorInfo:29650
Eduard
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Location: Armenia,Yerevan

### My algorithm:

///// c[] - array of coefficients p(x)

.....

lc = 0;
for (i = 1; i < n; ++i) {
cc = k*lc + c[i - 1]; /// calculating coefficient for q(x)
printf(" %ld", cc); /// out coefficient for q(x)
lc = cc;
}

cc = k*lc + c[i - 1]; /// calculating reminder r
printf("\nr = %ld\n", cc); /// out reminder r

....

May be you can give me some tests?
Victor Barinov
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Joined: Sun Oct 03, 2004 10:03 am

### how about "q(x) = a*x"?

Hi.

for example

Code: Select all
`31`

or

q(x) = x
q(x) = 2 * x

I think that if your algorithm is correct,

you will get accepted

(Check for output format, too )
Sorry For My Poor English..
wook
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Location: Korea, Republic Of

### output???

Can anybody give me correct output file for this input:

3
1 -7 15 -8
3
1 -7 15 -9
3
1
3
0 0 0 0 5
Victor Barinov
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Joined: Sun Oct 03, 2004 10:03 am

My AC solution outputs.
Output
Code: Select all
`q(x): 1 -4 3r = 1q(x): 1 -4 3r = 0q(x):r = 1q(x): 0 0 0 0r = 5`
someone who like to solve informatic problems.
http://acm.uva.es/cgi-bin/OnlineJudge?AuthorInfo:29650
Eduard
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Posts: 183
Joined: Fri Sep 26, 2003 2:54 pm
Location: Armenia,Yerevan

there maybe some residue spaces/endlines in the end of input.
bugzpodder
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Joined: Fri Jun 13, 2003 10:46 pm

### I got AC.

My mistake was very silly. I forgot that k may be negative
But now I got AC, and I very happy.
Thanks to everybody who tried to help me!
Victor Barinov
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Posts: 24
Joined: Sun Oct 03, 2004 10:03 am

I find something interesting, when I implemented it, I actually have
q(x) : 0

if p(x) is constant and get WA.

So much for unnecessary steps
yiuyuho
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Location: United States

### 10719 Quotient Polynomial getting TLE

How on earth can i get TLE in 10719 ... any ideas ????

heres my code

#include<stdio.h>
#include<math.h>
#include<ctype.h>
#define MAXN 10020

long p[MAXN],q[MAXN],r;
char input[MAXN*12];

void swap(long &a,long &b)
{
long temp;
temp=a;
a=b;
b=temp;
}

{
long i,j,n;

gets(input);

n=0;

for(i=0;input[i];i++)
{
sscanf(&input[i],"%ld",&p[n++]);

do{
i++;
}while(input[i]=='-' || isdigit(input[i]));

if(input[i]==0)
break;
}

--n;
for(i=0,j=n;i<=j;i++,j--)
swap(p[i],p[j]);

return n;
}

int main()
{
long i,n,k;

// freopen("in10719.txt","r",stdin);

while(scanf("%ld\n",&k)==1)
{

q[n]=0;

for(i=1;i<=n;i++)
{
q[n-i]=p[n-i+1]+k*q[n-i+1];
}

r=p[0]+k*q[0];

printf("q(x):");

for(i=n-1;i>=0;i--)
{
printf(" %ld",q[i]);
}

printf("\nr = %ld\n\n",r);
}

return 0;
}
soumit
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### Re: 10719 Quotient Polynomial getting TLE

soumit wrote:
sscanf(&input[i],"%ld",&p[n++]);

use only input as the first param.
but looking at it i think there may be some problem in input
parsing.
try to use strtok().
Zuberul
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Location: dhaka

I'm not sure if this TLE is for input parsing. But I'm pretty much sure that if you use strtok(), you'll get TLE. I took input character by character in this problem.

Regards
Sanny
Sanny
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sanny wrote:But I'm pretty much sure that if you use strtok(), you'll get TLE

Not quite..
.. I used strtok() and got it AC.

sohel
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Joined: Thu Jan 30, 2003 5:50 am
Location: University of Texas at San Antonio

Then maybe you use strtok() in a more efficient way than me. During contest time, I got TLE on this problem for using strtok().

Regards
Sanny
Sanny
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Joined: Sat Feb 14, 2004 3:59 pm
Location: BUET

I use strtok() in the standard way, I think.

Code: Select all
`#include<string.h>#include<vector>using namespace std;int main() { char *p; int a; char str[1000]; vector<int> V; gets(str); p = strtok(str, " "); sscanf(p, "%d", &a); V.push_back(a); while(1) {  p = strtok(NULL, " ");  if( !p ) break;  sscanf(p, "%d", &a);  V.push_back(a); }}`

sohel
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Posts: 862
Joined: Thu Jan 30, 2003 5:50 am
Location: University of Texas at San Antonio

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